You're much much stronger than you seem to think you are in the A Q Q J hand.
One of the limp-callers immediately bet the pot for $63. Two of the limp-callers folded, and the preflop raiser went all-in for $93. The action came back to me with $207 in the pot that I could cover. (That number assumed the auto-call from the first bettor for his last dollars.) I'd just sat down, so I had $87 left in front of me, and the pot was laying me 1-to-2.37.
Not a big diff, but I count immediate pot odds of (63 + 63 + 87) : 87 or 2.45:1 (counting the raiser's bet as 87 rather than 93, since you are all in for 87). If the original flop bettor calls the raise, you'll be getting (63 + 87 + 87) : 87 or 2.72:1.
You have top set on a flop of Q J 7. Let's ignore the J in your hand for a moment. With top set, if your pairing cards aren't dead, you are about 2:1 against making a boat by the river. So, using intuition rather than math, a heads up Omaha opponent can't be more than a 2:1 favorite over you if you hold top set for the current nuts. (In a game with more hole cards—e.g., 8-card Omaha—this wouldn't be true, since an opponent could hold cards that interfere with your boat draw PLUS cards that give him a monster draw to beat you. With 4-card Omaha, though, adding interference cards detracts too much from your opponent's drawing chances. The exact numbers depend on the mechanics of poker draws, which is why we're intuiting rather than proving this.)
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Stronger than you think with Ac Qc Qd Jd, part 1
Date: 2005-02-10 20:15 (UTC)Not a big diff, but I count immediate pot odds of (63 + 63 + 87) : 87 or 2.45:1 (counting the raiser's bet as 87 rather than 93, since you are all in for 87). If the original flop bettor calls the raise, you'll be getting (63 + 87 + 87) : 87 or 2.72:1.
You have top set on a flop of Q